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Ticket #0002101 User: anonymous


TypeBug Statusdismissed Date22-Jan-2014 02:27
Versionr3 master CategoryDatatype Submitted byfork
PlatformAll Severitymajor Prioritynormal

Summary Variables containing LIT-WORD! decay to WORD! in evaluator, shouldn't (?)
Description I realize that when the evaluator hits a LIT-WORD! literal, then by default it needs to become a WORD!. That makes obvious sense.

>> type? 'x
== word!

If you *really* wanted a lit-word, you need to quote it:

>> type? quote 'x
== lit-word!

But I find this puzzling:

>> foo: quote 'x
== 'x

>> type? foo
== word!

The variable holds a lit-word!, so what is the purpose of forcing this to have to be a get-word! case?

>> type? :foo
== lit-word!

It makes meta-programming difficult when your lit-word! tinkertoys are acting like this. I understand that functions must default to invocation for the language to work, but this doesn't seem to have value. What is the motivation?

Note that PARSE does not decay them:

>> parse [x x x] [3 foo]
== true
Example code
Current behavior:

    >> foo: quote 'x
    == 'x

    >> type? foo
    == word!

Desired behavior:

    >> foo: quote 'x
    == 'x

    >> type? foo
    == lit-word!

Assigned ton/a Fixed in- Last Update20-Sep-2015 07:12

22-Jan-2014 02:45

Possibly a duplicate of #1434 (esp. see Ladislav's comment 0003180 / 5-May-2011 12:39, which also suggests the same desired behaviour).
20-Feb-2014 21:04

Ladislav's solution implemented in

Date User Field Action Change
20-Sep-2015 07:12 abolka Status Modified pending => dismissed
26-Feb-2014 16:17 Ladislav Severity Modified minor => major
20-Feb-2014 21:04 BrianH Comment : 0004252 Added -
20-Feb-2014 21:04 BrianH Category Modified Unspecified => Datatype
20-Feb-2014 21:04 BrianH Status Modified submitted => pending
20-Feb-2014 21:04 BrianH Type Modified Issue => Bug
22-Jan-2014 02:45 abolka Comment : 0004218 Added -
22-Jan-2014 02:28 fork Description Modified -
22-Jan-2014 02:28 fork Code Modified -
22-Jan-2014 02:27 fork Ticket Added -